Finite Math Examples

Find the LCM y , v , m , b , l , h , v , f , s , i
y , v , m , b , l , h , v , f , s , i
Step 1
Since y,v,m,b,l,h,v,f,s,i contains both numbers and variables, there are two steps to find the LCM. Find LCM for the numeric part 1,1,1,1,1,1,1,1,1,1 then find LCM for the variable part y1,v1,m1,b1,l1,h1,v1,f1,s1.
Step 2
The LCM is the smallest positive number that all of the numbers divide into evenly.
1. List the prime factors of each number.
2. Multiply each factor the greatest number of times it occurs in either number.
Step 3
The number 1 is not a prime number because it only has one positive factor, which is itself.
Not prime
Step 4
The LCM of 1,1,1,1,1,1,1,1,1,1 is the result of multiplying all prime factors the greatest number of times they occur in either number.
1
Step 5
The factor for y1 is y itself.
y1=y
y occurs 1 time.
Step 6
The factor for v1 is v itself.
v1=v
v occurs 1 time.
Step 7
The factor for m1 is m itself.
m1=m
m occurs 1 time.
Step 8
The factor for b1 is b itself.
b1=b
b occurs 1 time.
Step 9
The factor for l1 is l itself.
l1=l
l occurs 1 time.
Step 10
The factor for h1 is h itself.
h1=h
h occurs 1 time.
Step 11
The factor for v1 is v itself.
v1=v
v occurs 1 time.
Step 12
The factor for f1 is f itself.
f1=f
f occurs 1 time.
Step 13
The factor for s1 is s itself.
s1=s
s occurs 1 time.
Step 14
The LCM of y1,v1,m1,b1,l1,h1,v1,f1,s1 is the result of multiplying all prime factors the greatest number of times they occur in either term.
yvmblhfs
Step 15
Multiply yvmblhf by s.
yvmblhfs
y,v,m,b,l,h,v,f,s,i
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